1、时间格式化：含有秒

export const formatTime = (date) => {    var year = date.getFullYear()    var month = date.getMonth() + 1    var day = date.getDate()    var hour = date.getHours()    var minute = date.getMinutes()    var second = date.getSeconds()    return year + '-' + month + '-' + day + ' ' + hour + ':' + minute + ':' + second};

2、日期格式化       例如：2019年04月09日

export const formatTimeText = (date) => {    var time = new Date(date.replace(/-/g, "/"))    var year = time.getFullYear()    var month = time.getMonth() + 1    var day = time.getDate()    return year + ' 年 ' + month + ' 月 ' + day + ' 日'};

日期加减法 date参数为计算开始的日期，days为需要减的天数，格式:minusDate('20179-04-09',20) 日期加'0'

export const minusDate =(date,days) => {    var d=new Date(date);    var tian = d.setDate(d.getDate() - days);    var m=d.getMonth()+1;    return d.getFullYear()+'-'+m+'-'+d.getDate();}

日期格式化        例如：2019-04-09

export const formatDate = (day) => {  var Year = 0;  var Month = 0;  var Day = 0;  var CurrentDate = '';  //初始化时间  Year = day.getFullYear();//ie火狐下都可以  Month = day.getMonth() + 1;  Day = day.getDate();  CurrentDate += Year + '-';  if (Month >= 10) {    CurrentDate += Month + '-';  }  else {    CurrentDate += '0' + Month + '-';  }  if (Day >= 10) {    CurrentDate += Day;  }  else {    CurrentDate += '0' + Day;  }  return CurrentDate;};

日期计算小时数

export const calcRemainderTime = (time) => {  if (time <= 0) {    return '0小时'  }  var day = Math.floor(time / 24)  var hour = time % 24  time = (day === 0 ? time + '小时' : day + '天' + (hour === 0 ? '' : hour + '小时'))  return time}

默认七天

export const default7Day = () =>{    let now = formatDate(new Date())    let defaultEndDate = minusDate(now,1)    let defaultStartDate = minusDate(now,7)    let dateObj = {        beginDate: defaultStartDate,        endDate: defaultEndDate    }    return dateObj;}

两个时间相差天数

/** * 两个时间相差天数 *  sDate1和sDate2是2012-12-12格式 *  开始日期：00：00：00 *  结束日期：23：59：59 */export const dateDifference = (sDate1, sDate2) => {    var dateSpan,        tempDate,        iDays;    sDate1 = Date.parse(sDate1);    sDate2 = Date.parse(sDate2);    dateSpan = sDate2 - sDate1;    dateSpan = Math.abs(dateSpan);    iDays = Math.floor(dateSpan / (24 * 3600 * 1000));    return iDays + 1};